True of False?

E=exchange rate

Suppose E $/euros = 3/2 and E $/pounds = 2, and there is no trade friction, the no arbitrage condition implies
that E pounds/euros = 2

2 answers

False. Think it through.
You have $/euros = 3/2 which means $3 = 2E. Also, you have 2E=1L. Ergo, $3=1L.
so the arbitrage condition should be E pounds/euros=3/4. ( i got this by multiplying 1/2 and 3/2 )

Is this correct?