Asked by Emily
Divide. Show all work. Make sure to simplify. Assume no denominator equals zero x^2-144/x^2+7x-60 divided by 3x-36/9x-45
I'm really confused on this and if anyone can help, I'd appreciate it. Thanks!
I'm really confused on this and if anyone can help, I'd appreciate it. Thanks!
Answers
Answered by
Steve
x^2-144 = (x-12)(x+12)
x^2+7x-60 = (x+12)(x-5)
3x-36 = 3(x-12)
9x-45 = 9(x-5)
So, since dividing by a fraction is the same as multiplying by its reciprocal, we really have
(x-12)(x+12) / (x-5)(x+12) * 9(x-5) / 3(x-12)
Now you can see that almost everything cancels out, leaving you with just a value of
3
There's an (x-12) top and bottom, (x+12) top and bottom, and (x-5) top and bottom.
x^2+7x-60 = (x+12)(x-5)
3x-36 = 3(x-12)
9x-45 = 9(x-5)
So, since dividing by a fraction is the same as multiplying by its reciprocal, we really have
(x-12)(x+12) / (x-5)(x+12) * 9(x-5) / 3(x-12)
Now you can see that almost everything cancels out, leaving you with just a value of
3
There's an (x-12) top and bottom, (x+12) top and bottom, and (x-5) top and bottom.
Answered by
Emily
Thank you! That makes so much more sense now!
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