Asked by Mary
If 87.3 mL of 0.225M KOH solution is mixed with 44.4 mL of 0.313M H2SO4 solution, would the resulting mixture be acidic, basic or neutral?
Answers
Answered by
DrBob222
2KOH + H2SO4 --> K2SO4 + 2H2O
mols KOH = M x L = estimated 0.01964 and it will react with 1/2*(0.01964) = estd 0.00982 mols H2SO4.
How much H2SO4 do you have? That's M x L = estd 0.0139 so you have more than enough H2SO4 to exactly neutralize it. That means an excess of H2SO4 which will make the solution .......
mols KOH = M x L = estimated 0.01964 and it will react with 1/2*(0.01964) = estd 0.00982 mols H2SO4.
How much H2SO4 do you have? That's M x L = estd 0.0139 so you have more than enough H2SO4 to exactly neutralize it. That means an excess of H2SO4 which will make the solution .......
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