Asked by leelee kay
Write the equations in logarithmic form.
(a)
729 = 93(9 to the 3rd power)
(b)
25 = 1/5 −2( 1/5 to the -2 power)
a = bc ( c squared)
(a)
729 = 93(9 to the 3rd power)
(b)
25 = 1/5 −2( 1/5 to the -2 power)
a = bc ( c squared)
Answers
Answered by
MathMate
729=9³
log<sub>9</sub>729 = 3
25 = (1/5)<sup>-2</sup>
log<sub>(1/5)</sub>25 = -2
for a=bc²
rearrange to
(a/b) = c²
and proceed similar to above.
log<sub>9</sub>729 = 3
25 = (1/5)<sup>-2</sup>
log<sub>(1/5)</sub>25 = -2
for a=bc²
rearrange to
(a/b) = c²
and proceed similar to above.
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