Asked by swastika

Calculate the molality of sulphuric acid solution in which mole fraction of water is .85
Answered by DrBob222
Take enough solution to have 1 mol total. That means you have 0.15mol H2SO4 and 0.85 mol H2O. Convert H2O to grams which is 0.85 x (18 g H2O/mol H2O) = approx 15
Then m = mol/kg solvent
m = 0.15/0.015 = ? estimated.
Answered by asif karim
not bad
Answered by Mina
Ans :9.8
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