Asked by Barbara
can you solve the quadratic function?
y = 2x^2 + 3
y = 2x^2 + 3
Answers
Answered by
Bosnian
2 x ^ 2 + 3 = 0 Subtract 3 to both sides
2 x ^ 2 + 3 - 3 = 0 - 3
2 x ^ 2 = - 3 Divide both sides by 2
x ^ 2 = - 3 / 2 Take square root of both sides
x = + OR - square root ( - 3 / 2 )
x = + OR -
i * square root ( - 3 / 2 )
2 x ^ 2 + 3 - 3 = 0 - 3
2 x ^ 2 = - 3 Divide both sides by 2
x ^ 2 = - 3 / 2 Take square root of both sides
x = + OR - square root ( - 3 / 2 )
x = + OR -
i * square root ( - 3 / 2 )
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