Asked by Denis
indium-115 has a half life of 4.5 hours, if you start with a 12.0mg sample of indium-115, how much will remain after 13.5 hours
Answers
Answered by
bobpursley
two ways: remaining=12mg*(1/2)^13.5/4.5
you can do that by putting this in your google search window:12*(1/2)^(13.5/4.5)=
Nerd way:
remaining=12.5*e^(.693*13.5/4.5)=
and put that in your google search window
you can do that by putting this in your google search window:12*(1/2)^(13.5/4.5)=
Nerd way:
remaining=12.5*e^(.693*13.5/4.5)=
and put that in your google search window
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
Solve for k and substitute into the below equation.
ln(No/N) = kt
No = 12.0 mg
N = ? mg
k = from above
t = 13.5 hrs
Solve for k and substitute into the below equation.
ln(No/N) = kt
No = 12.0 mg
N = ? mg
k = from above
t = 13.5 hrs
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.