Asked by Anonymous
An athlete stretches a spring an extra 15.9 cm beyond its initial length. How much energy has he transferred to the spring
Answers
Answered by
MathMate
If k is the spring constant in N/m, and if the initial length is the natural (stress length), then
energy=work done
=(1/2)kx² joules
where
x=stretching in metres
=15.9cm=0.159 m
energy=work done
=(1/2)kx² joules
where
x=stretching in metres
=15.9cm=0.159 m
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