Asked by Kiirsty
a) expand and simplify: (4x-3)(x+1)
i get 4x^2+x-3 ?
b) factorise: 2x^2 + 13x + 15
c) find y-int, x-int and vertex of:
y= x^2-3x-4
i get y-int = -4, but loose it from there :(
i get 4x^2+x-3 ?
b) factorise: 2x^2 + 13x + 15
c) find y-int, x-int and vertex of:
y= x^2-3x-4
i get y-int = -4, but loose it from there :(
Answers
Answered by
MathMate
A. correct
B. look for two numbers m,n such that mn=2*15=30, and m+n=13.
m and n are therefore 10 and 3.
2x²+<i>10x</i> + <i>3x</i>+15
=2x(x+5) + 3(x+5)
=(2x+3)(x+5)
C. y-intercept: correct.
X-intercept=zeroes.
Factorize y=x²-3x-4=(x+1)(x-4) to get the zeroes.
The vertex is located at x=-b/2a=-(-3)/2=1.5
and corresponding y is f(1.5)=-6.25
The vertex can also be found by completing the square.
B. look for two numbers m,n such that mn=2*15=30, and m+n=13.
m and n are therefore 10 and 3.
2x²+<i>10x</i> + <i>3x</i>+15
=2x(x+5) + 3(x+5)
=(2x+3)(x+5)
C. y-intercept: correct.
X-intercept=zeroes.
Factorize y=x²-3x-4=(x+1)(x-4) to get the zeroes.
The vertex is located at x=-b/2a=-(-3)/2=1.5
and corresponding y is f(1.5)=-6.25
The vertex can also be found by completing the square.
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