Asked by Mark
Ammonia is produced when Nitrogen gas reacts with Hydrogen gas, as shown by the equation below:
N2 + 3H2 --> 2NH3
If the percentage yield is 90%, what would be your experimental yield of NH3 if 145.8g of N2 react?
2) 2Mg + O2 --> 2MgO
A) If 50g of Mg reacts with 50g of O2, what is the limiting reactants?
B) How much excess reactant is left over
C) How much product is produced?
N2 + 3H2 --> 2NH3
If the percentage yield is 90%, what would be your experimental yield of NH3 if 145.8g of N2 react?
2) 2Mg + O2 --> 2MgO
A) If 50g of Mg reacts with 50g of O2, what is the limiting reactants?
B) How much excess reactant is left over
C) How much product is produced?
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