Question

Ammonia can be produced in a two-step process. First, nitrogen reacts with red-hot magnesium to form magnesium nitride. Then magnesium nitride reacts with water to form magnesium hydroxide and ammonia.

How many grams of magnesium would we have to start with to prepare 15.0 grams of ammonia?
For the balanced chemical formulas are:
3Mg(s) + N2(g) --> Mg3N2(s)
Mg2N2(s) + 6H2O --> 3Mg(OH)2(aq) + 2NH3(aq)

I'm still struggling with finding the grams of Magnesium needed to start with to prepare 15.0 grams of ammonia. I don't know how to do reverse stoichiometry. Please help. Thanks

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