E[XY] = 1
var[XY] = 7/9
p(XY >= 1) = ??
Let X and Y be independent random variables, each uniformly distributed on the interval [0,2].
Find the mean and variance of XY.
E[XY]=
var[XY]=
Find the probability that XY≥1. Enter a numerical answer.
P(XY≥1)=
3 answers
p(XY >= 1) = 2/5
p(XY >= 1) = 0.40343