Asked by Anonymous

Let X and Y be independent random variables, each uniformly distributed on the interval [0,2].

Find the mean and variance of XY.

E[XY]= 1

var[XY]= ???

Find the probability that XY≥1. Enter a numerical answer.

P(XY≥1)= ???

Answers

Answered by Anonymous
please solve P(XY≥1)=
Answered by AL
var(XY) = E[(XY)^2] - (E[XY]^2) = 7/9
Answered by RVE
please solve P(XY≥1)= 0.40343
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