Asked by VIC

Determine the numbers of liters of oxygen required to oxidize 46 g of carbon to make carbon monoxide at STP?

Answers

Answered by Damon
22.4 liters/mole for perfect gas at STP

C + O2 --> CO2

46 g of C which is 12 grams/mole
so we need 46/12 = 3.83 moles of carbon and 3.83 moles of O2

3.83 * 22.4 = 86 liters
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions