Asked by VIC
Determine the numbers of liters of oxygen required to oxidize 46 g of carbon to make carbon monoxide at STP?
Answers
Answered by
Damon
22.4 liters/mole for perfect gas at STP
C + O2 --> CO2
46 g of C which is 12 grams/mole
so we need 46/12 = 3.83 moles of carbon and 3.83 moles of O2
3.83 * 22.4 = 86 liters
C + O2 --> CO2
46 g of C which is 12 grams/mole
so we need 46/12 = 3.83 moles of carbon and 3.83 moles of O2
3.83 * 22.4 = 86 liters
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