Asked by Andres
determine real numbers a and b so that the expression 8sin^2(theta) + 2cos^2(theta) can be rewritten as (a)sin^2(theta) + b?
If you can help me out on how to start it would be great.
If you can help me out on how to start it would be great.
Answers
Answered by
MathMate
Use the identity:
sin²(x)+cos²(x)=1
In
8sin^2(theta) + 2cos^2(theta)
regroup to get:
6sin^2(theta) + 2(sin^2(theta)+cos^2(theta))
=6sin^2(theta) + 2
QED
sin²(x)+cos²(x)=1
In
8sin^2(theta) + 2cos^2(theta)
regroup to get:
6sin^2(theta) + 2(sin^2(theta)+cos^2(theta))
=6sin^2(theta) + 2
QED
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