Asked by Andres
                determine real numbers a and b so that the expression 8sin^2(theta) + 2cos^2(theta) can be rewritten as (a)sin^2(theta) + b? 
If you can help me out on how to start it would be great.
            
        If you can help me out on how to start it would be great.
Answers
                    Answered by
            MathMate
            
    Use the identity:
sin²(x)+cos²(x)=1
In
8sin^2(theta) + 2cos^2(theta)
regroup to get:
6sin^2(theta) + 2(sin^2(theta)+cos^2(theta))
=6sin^2(theta) + 2
QED
    
sin²(x)+cos²(x)=1
In
8sin^2(theta) + 2cos^2(theta)
regroup to get:
6sin^2(theta) + 2(sin^2(theta)+cos^2(theta))
=6sin^2(theta) + 2
QED
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