Asked by Ann
Find A so that
5log(base5)16807 − 3log(base5)7 = log (base5)A
I don't even know how to start this one...should I remove the 5 and 3 in front of the logs?
5log(base5)16807 − 3log(base5)7 = log (base5)A
I don't even know how to start this one...should I remove the 5 and 3 in front of the logs?
Answers
Answered by
Reiny
log<sub>5</sub> 16807^5 - log<sub>5</sub>7^3 = log<sub>5</sub>A
log<sub>5</sub> (16807^5/7^3) = log<sub>5</sub>A
A = 16807^5 / 7^3
= 49(16807)^4
= appr 3.91 x 10^18
log<sub>5</sub> (16807^5/7^3) = log<sub>5</sub>A
A = 16807^5 / 7^3
= 49(16807)^4
= appr 3.91 x 10^18
Answered by
Ann
oh right you just have to factor out the logbase5...thank you
Answered by
Damon
You are NOT factoring it out
You are saying that if
log x = log y
then x = y
You are saying that if
log x = log y
then x = y
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