Find A so that

Question

5log(base5)16807 − 3log(base5)7 = log (base5)A

I don't even know how to start this one...should I remove the 5 and 3 in front of the logs?

Answer 1

log₅ 16807^5 - log₅7^3 = log₅A
log₅ (16807^5/7^3) = log₅A

A = 16807^5 / 7^3
= 49(16807)^4
= appr 3.91 x 10^18

Answer 2

oh right you just have to factor out the logbase5...thank you

Answer 3

You are NOT factoring it out
You are saying that if
log x = log y
then x = y