Ask a New Question

Question

Solve for x:
log base5 (4x) + log base5 (x) = log base5 (64)
11 years ago

Answers

Damon
all logs base 5

64 is 4^3
log (4 x^2) = log 64 = log (4^3)
so
4 x^2 = 4^3
x = 4
11 years ago

Related Questions

log(base5)x+log(base25)x+log(base125)x=33 solve for x 1. Solve 3=log8+3logx 2. Solve 2logx-log4=0 Find A so that 5log(base5)16807 − 3log(base5)7 = log (base5)A I don't even know how to start... If Log27 in base5=x and Log5 in base3=y., find xy LOG(base5)(3/5)+3log(base5)(15/2)-log(base5)(81/8) 1/3log(base5) 3x + log(base5) 4=3 what I meant is: 1/3=one-third ,log5= log(base5) Solve and show steps. Solve the formula for the indicated variable. T=3U/E , solve for U Solve the equation. Solve for d. 2/7d-1/5=1/9 solve and show steps to solve : x^2 + 4 = 53 1/3log(base5) 3x + log(base5) 4=3
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use