Asked by chelsea
identify the conic section. Write in standard form and graph.
5x^2-6y^2-30x-12y+9=0
5x^2-6y^2-30x-12y+9=0
Answers
Answered by
Reiny
5x^2-6y^2-30x-12y+9=0
lets complete the square
5(x^2 - 6x + ___) -6(y^2 + 2y + ___) = -9
5(x^2 - 6x + 9) -6(y^2 + 2y + 1) = -9 + 45 - 6
5(x-3)^2 - 6(y+1)^2 = 30
divide both sides by 30
(x-3^2 /6 - (y+1)^2 /5 = 1
I will leave it up to you to identify the conic and its properties.
lets complete the square
5(x^2 - 6x + ___) -6(y^2 + 2y + ___) = -9
5(x^2 - 6x + 9) -6(y^2 + 2y + 1) = -9 + 45 - 6
5(x-3)^2 - 6(y+1)^2 = 30
divide both sides by 30
(x-3^2 /6 - (y+1)^2 /5 = 1
I will leave it up to you to identify the conic and its properties.
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