Asked by tenzin
A soccer ball is kicked horizontally at 16.1 m/s off the top of a field house and lands 37.5 metes from the base of the field house. Determine the height of the field house.
Answers
Answered by
MathMate
Time, t, to reach ground = Δx/vix
= 2.329 s
Use kinematics equation
Δy=viy*t+(1/2)g(t)²
= 10.92 m.
(g=-9.81 m/s²), viy=0)
= 2.329 s
Use kinematics equation
Δy=viy*t+(1/2)g(t)²
= 10.92 m.
(g=-9.81 m/s²), viy=0)
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