Asked by sara
a pendulum is swinging back and forth once every 1.25 second, how much longer should the pendulum be to increase its period by 0.200 second
Answers
Answered by
Devron
t=2pi*sqrt(L/g)
t=1.25=2pi*sqrt(L/9.8m/s)
Solve for L
9.8m/s^2*(1.25/2pi)^2=L
L=0.388m
I want to increase the period by 0.200 seconds. How long should I increase the length of the pendulum? The new period will be 1.45 seconds. Use the above equation and solve for L:
t=1.45=2pi*sqrt(L/9.8m/s)
9.8m/s^2*(1.45/2pi)^2=L
L=0.522m
0.522m-0.388m=0.134m=13.4cm
t=1.25=2pi*sqrt(L/9.8m/s)
Solve for L
9.8m/s^2*(1.25/2pi)^2=L
L=0.388m
I want to increase the period by 0.200 seconds. How long should I increase the length of the pendulum? The new period will be 1.45 seconds. Use the above equation and solve for L:
t=1.45=2pi*sqrt(L/9.8m/s)
9.8m/s^2*(1.45/2pi)^2=L
L=0.522m
0.522m-0.388m=0.134m=13.4cm
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.