Asked by Me and I

Please help me go through this

F = q1q2/r^2, i know this is the equation, but i don't know how to get the answer, please help.

What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? Show your work. (µC = 1.0 × 10^–6 C)

Answered by Me and I
(9x 10^9)/(.05m)^2, is this what i should be calculating?
Answered by Devron
F=KoQ1Q2/r^2

Where

Ko= 8.988 x 10^9 N*m^2/C^2
Q1=+2 µC=2 x 10^-9 C
Q2=-2 µC=-2 x 10^-9 C
and
r=5.0 cm=0.050 m

***Notice that Coulomb's constant contains meters and that it contains coulombs and not microcoulombs.

***Convert centimeters to meters and coulombs and not microcoulombs.


Solve for F:


F=(8.988 x 10^9 N*m^2/C^2)*(2 x 10^-9 C)(-2 x 10^-9 C)/(0.050 m)^2

F==(8.988 x 10^9 N*m^2/C^2)*(4 x 10^-18 C^2)/(0.050 m)^2

F=?

I'll let you take it from here.
Answered by Me and I
ty so much :)
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