Question
1. Jasmine rode a horse down a path headed north. she started from rest and then accelerated at 0.5 m/s2 for 12 seconds and then travelled at a constant speed for 28 seconds.
a.) what was her velocity after 12 seconds?
b.) what was jasmines displacement after 10 seconds?
c.) how far did Jasmine travel during her 40 s ride?
d.) draw a velocity time graph for her motion
2. Bryce can ride his bicycle at an average speed of 18 m/s and Ally rides with an average speed of 23 m/s. ally gives bryce a 200 m Headstart in a 1 km (1000m) race. use a distance time graph to solve the following questions:
a.) who wins the race? explain your answer
b.) how many meters separate the 2 cyclists at the end of the race?
a.) what was her velocity after 12 seconds?
b.) what was jasmines displacement after 10 seconds?
c.) how far did Jasmine travel during her 40 s ride?
d.) draw a velocity time graph for her motion
2. Bryce can ride his bicycle at an average speed of 18 m/s and Ally rides with an average speed of 23 m/s. ally gives bryce a 200 m Headstart in a 1 km (1000m) race. use a distance time graph to solve the following questions:
a.) who wins the race? explain your answer
b.) how many meters separate the 2 cyclists at the end of the race?
Answers
Devron
1.
a.)
Vf=Vi +at
Where
Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s
Solve for Vf:
Vf=0m/s +(0.5m/s^2)*(12s)
Vf=6m/s
b.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=10s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2
d=0 +25m
d=25m
c.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=40s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2
d=0 +400m
d=400m
d.)
Plot distance Vs velocity
x axis =displacement and y=velocity
2.
****Plot distance on the x-axis and time (distance/velocity) on the y-axis.
***Remember, Bryce only has to travel 800m.
a.)
d=r*t
Where
r=velocity
t=?
and
d=displacement.
Bryce
d=800m
r=18m/s
t=?
800=18m/s*t
t=800m/18m/s
t=44.4s
Ally
d=1,000m
r=23m/s
t=?
1,000m=23m/s*t
t=1,000m/23m/s
t=43.5s
Ally wins.
b.)
Bryce wins the race in 43.4s. How far is Ally from the finish line when Bryce reaches the finish line?
d=18 m/s*43.4s
d1=781.2m
Total distance=d1+d2=781.2m + 200m=981.2m
1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.
a.)
Vf=Vi +at
Where
Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s
Solve for Vf:
Vf=0m/s +(0.5m/s^2)*(12s)
Vf=6m/s
b.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=10s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2
d=0 +25m
d=25m
c.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=40s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2
d=0 +400m
d=400m
d.)
Plot distance Vs velocity
x axis =displacement and y=velocity
2.
****Plot distance on the x-axis and time (distance/velocity) on the y-axis.
***Remember, Bryce only has to travel 800m.
a.)
d=r*t
Where
r=velocity
t=?
and
d=displacement.
Bryce
d=800m
r=18m/s
t=?
800=18m/s*t
t=800m/18m/s
t=44.4s
Ally
d=1,000m
r=23m/s
t=?
1,000m=23m/s*t
t=1,000m/23m/s
t=43.5s
Ally wins.
b.)
Bryce wins the race in 43.4s. How far is Ally from the finish line when Bryce reaches the finish line?
d=18 m/s*43.4s
d1=781.2m
Total distance=d1+d2=781.2m + 200m=981.2m
1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.
Devron
Typo correction. Look for ^&***" for correction .
1.
a.)
Vf=Vi +at
Where
Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s
Solve for Vf:
Vf=0m/s +(0.5m/s^2)*(12s)
Vf=6m/s
b.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=10s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2
d=0 +25m
d=25m
c.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=40s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2
d=0 +400m
d=400m
d.)
Plot distance Vs velocity
x axis =displacement and y=velocity
2.
****Plot distance on the x-axis and time (distance/velocity) on the y-axis.
***Remember, Bryce only has to travel 800m.
a.)
d=r*t
Where
r=velocity
t=?
and
d=displacement.
Bryce
d=800m
r=18m/s
t=?
800=18m/s*t
t=800m/18m/s
t=44.4s
Ally
d=1,000m
r=23m/s
t=?
1,000m=23m/s*t
t=1,000m/23m/s
t=43.5s
Ally wins.
b.)
^&***" Ally wins the race in 43.4s. How far is Bryce from the finish line when Ally reaches the finish line?" ***^&
d=18 m/s*43.4s
d1=781.2m
Total distance=d1+d2=781.2m + 200m=981.2m
1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.
1.
a.)
Vf=Vi +at
Where
Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s
Solve for Vf:
Vf=0m/s +(0.5m/s^2)*(12s)
Vf=6m/s
b.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=10s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2
d=0 +25m
d=25m
c.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=40s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2
d=0 +400m
d=400m
d.)
Plot distance Vs velocity
x axis =displacement and y=velocity
2.
****Plot distance on the x-axis and time (distance/velocity) on the y-axis.
***Remember, Bryce only has to travel 800m.
a.)
d=r*t
Where
r=velocity
t=?
and
d=displacement.
Bryce
d=800m
r=18m/s
t=?
800=18m/s*t
t=800m/18m/s
t=44.4s
Ally
d=1,000m
r=23m/s
t=?
1,000m=23m/s*t
t=1,000m/23m/s
t=43.5s
Ally wins.
b.)
^&***" Ally wins the race in 43.4s. How far is Bryce from the finish line when Ally reaches the finish line?" ***^&
d=18 m/s*43.4s
d1=781.2m
Total distance=d1+d2=781.2m + 200m=981.2m
1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.
Samaira
Thank u so much :)