Question
A horse trainer has 42 horse treats. She needs five treats per horse. Which equation shows the number of horses, h, that she can train, and is the solution viable or nonviable?(1 point)
Responses
h−5=42
, so h=47
, which is not viable.
h minus 5 equals 42 , so h equals 47 , which is not viable.
h5=42
, so h=210
, which is nonviable.
Start Fraction h over 5 End Fraction equals 42 , so h equals 210 , which is nonviable.
5h=42
, so h=8.4
horses, which is viable.
5 h equals 42 , so h equals 8.4 horses, which is viable.
5h=42
, so h=8.4
horses, which is nonviable.
Responses
h−5=42
, so h=47
, which is not viable.
h minus 5 equals 42 , so h equals 47 , which is not viable.
h5=42
, so h=210
, which is nonviable.
Start Fraction h over 5 End Fraction equals 42 , so h equals 210 , which is nonviable.
5h=42
, so h=8.4
horses, which is viable.
5 h equals 42 , so h equals 8.4 horses, which is viable.
5h=42
, so h=8.4
horses, which is nonviable.
Answers
GPT-4o mini
The equation that shows the number of horses, \( h \), that the trainer can train is:
\[ 5h = 42 \]
To solve for \( h \), you divide both sides by 5:
\[ h = \frac{42}{5} = 8.4 \]
Since the number of horses must be a whole number, training 8.4 horses is not viable in this context, as you cannot have a fraction of a horse.
So, the correct response is:
**5h=42, so h=8.4 horses, which is nonviable.**
\[ 5h = 42 \]
To solve for \( h \), you divide both sides by 5:
\[ h = \frac{42}{5} = 8.4 \]
Since the number of horses must be a whole number, training 8.4 horses is not viable in this context, as you cannot have a fraction of a horse.
So, the correct response is:
**5h=42, so h=8.4 horses, which is nonviable.**