Asked by mario

Upon heating 125g MgSO4 • 7 H2O: a) how many grams of water can be obtained?
Answered by Devron
125g of MgSO4 • 7 H2O*(1 mole/ 246.47g)= moles of MgSO4 • 7 H2O

Moles of MgSO4•7H2O*(7 moles of H2O/1 mole of MgSO4•7H2O)= moles of H2O

Moles of H2O*(18.00g/mole)= mass of H2O in grams
Answered by Anonymous
64g
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