(a) the -x^2 means it opens downward
(b) set x=0 to get y-intercept
Since y = (1-x)(x-3) the x-intercepts are easy to see.
(c) as usual, the vertex is at x = -b/2a = 1. Find y(1).
Given the quadratic equation y = -x^2 + 2x + 3.
a) Will the graph turn upwards or downwards?
b) What are the coordinates of x and y intercepts?
c) What is the coordinate of the turning point?
d) Use your answer in parts (a,b,c and d) to sketch the graph.
1 answer
1 answer