Asked by G
Solving quardratic equations using factoring.
2X^2+2X-4=0
The book says the answer is -2,1.
I got the -2,1 but not in the order of
-2,1.
I used FOIL to solve. When I use -2,1 I don't can not solve. When I use
1,-2. I can solve.
I am not clear.
2X^2+2X-4=0
The book says the answer is -2,1.
I got the -2,1 but not in the order of
-2,1.
I used FOIL to solve. When I use -2,1 I don't can not solve. When I use
1,-2. I can solve.
I am not clear.
Answers
Answered by
Doug
The order is not important. The answer is x=-2 or x=1
Verify by substituting for x
2(-2)^2+2(-2)-4=0
8-4-4=0
0=0
2(1)^2+2(1)-4=0
2+2-4=0
0=0
Verify by substituting for x
2(-2)^2+2(-2)-4=0
8-4-4=0
0=0
2(1)^2+2(1)-4=0
2+2-4=0
0=0