Question

A 3.0 kg block is moved up a 37 degree incline under a constant horizontal force of 40.0 N. The coefficient of friction is 0.10 and the block is displaced 2.0 m up the incline. Calculate the change in the kinetic energy of the block.

Answer 1

Work is done on the block therefore kinetic energy is 1/2mv^2.

Identify the object - Block

Win or Wo = F*d
KEi or Keo = 1/2mv^2
Pei or Peo = mgh
Wf = coefficient of friction

-Is work done on the block from the start= Yes = Work in
-Is the object moving at the beginning = yes = Kei
-Is the object at a certain height or is it storing energy elastically - yes = Pei
-Is work done by the object - No (this would be work out or Wo)
-Is there work done against friction due to restive loss - Yes = Wf
-Is the object moving at the end - no (this would be Ke out)
-Is the object at a certain height or is it storing energy elastically at the end - No = Peo
-Does the object consume fuel - No - (This would be Ui)

So your equation would start off as Wi + Pei + Kei = Wf
Rearrange in Algebraic terms to determine Ke