A 1.7 kg block is moved at constant speed over a surface for which the coefficient of kinetic friction is 0.27. The displacement is 2 m. It is pushed by a force directed at 25 degrees below the horizontal.

Question

A 1.7 kg block is moved at constant speed over a surface for which the coefficient of kinetic friction is 0.27. The displacement is 2 m. It is pushed by a force directed at 25 degrees below the horizontal.
Find the work done on the block by: the force. How do you find the force?

drwls · Answer

Because the block moves at costant speed, the friction force F satisfies the equation F cos25 = 0.27 M*g = 4.50 N Solve that for F and multiply the result by 2 m for the work done, in Joules.

joe · Answer

ive been trying that but it doesnt work. for the force i get 4.96 and i find the work with that and its always wrong.