Question

a 2.00 L ballon at 25 degrees celcius and 745mmHg floats on an altitude where the temperature is 10 degrees celcius and the air pressure is 700mmHg. what is the new volume othe balloon
Use the combined gas law:

P1V1/T1=P2V2/T2

Where

P1=745mmHg
V1=2.00L
T1=273K+25=298.15K
P2=700mmHg
V2=?
T2=273.15+10=283.15K

Solve for V2:

V2=(P1/P2)*(T2/T1)*V1


Answer should contain three significant figures.
1.06L
Convert pressures from mmHg to atm then use combined gas law to solve for the new volume. You get 2.06 Liters

Related Questions

If 100g of zinc (c=377J/kg degrees celcius) at 95 degrees celcius is dropped into 60g of water conta... An expandable balloon contains 1400L of He at .950atm pressure and 18 degrees Celcius. At an altitud... A 2.8 kg gold bar at 99 degrees celcius is dropped into 0.21 kg of water at 23 degrees celcius... A ballon’s floats inside a stopped car when the car starts moving forward the ballon appears to move...