Asked by Christopher
                The length of a rectangular piece of steel  in a bridge is 3 meters less then double the width. The perimeter of the piece of steel is 24 meters Find the length and width of the piece of steel.
l=3-2w? is part of the formula?
            
        l=3-2w? is part of the formula?
Answers
                    Answered by
            Reiny
            
    Your definition of L is opposite of what it should be
L = 2W - 3
now use your definition of perimeter to solve
Perimeter of a rectange = 2W + 2L
2W + 2(2W-3) = 24
2W + 4W - 6 = 24
6W = 30
W = 5
then L = 2(5)-3 = 7
Your rectangle is 5 by 7
check:
P = 2(5)( + 2(7) = 10+14 = 24
    
L = 2W - 3
now use your definition of perimeter to solve
Perimeter of a rectange = 2W + 2L
2W + 2(2W-3) = 24
2W + 4W - 6 = 24
6W = 30
W = 5
then L = 2(5)-3 = 7
Your rectangle is 5 by 7
check:
P = 2(5)( + 2(7) = 10+14 = 24
                    Answered by
            Christopher
            
    Oh I got the formula backwards just had to flip it around. So yeah I got
L= 7 for the length of the piece of steel
and W=5 for the width of the piece of steel. I checked it and I got the same answer.
    
L= 7 for the length of the piece of steel
and W=5 for the width of the piece of steel. I checked it and I got the same answer.
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