Asked by Sarah
calculate number of atoms in 4.67 mol of Ca(NO3)2
I got:
2.81 X 10^24 C atoms or should it be 28.11 x 10^23 C atoms?
5.62 X 10^24 N atoms or should it be 9.34 x 10^23 N atoms?
1.69 x 10^25 O atoms....but are you allowed to do ^25 or should it be 168.7 X 10^23 O atoms I'm confused about exponents again.
also, do I need to worry about rounding to the correct number of signifcant digits when doing these questions?
I got:
2.81 X 10^24 C atoms or should it be 28.11 x 10^23 C atoms?
5.62 X 10^24 N atoms or should it be 9.34 x 10^23 N atoms?
1.69 x 10^25 O atoms....but are you allowed to do ^25 or should it be 168.7 X 10^23 O atoms I'm confused about exponents again.
also, do I need to worry about rounding to the correct number of signifcant digits when doing these questions?
Answers
Answered by
bobpursley
Always round to the correct number of significant digits.
Proper scientific notation is X.SY*10^qr
2.84*10^24
5.62*10^24
1.69*10^25 are all correct.
Proper scientific notation is X.SY*10^qr
2.84*10^24
5.62*10^24
1.69*10^25 are all correct.
Answered by
Sarah
would it have still been right if I didn't change the exponent, and say for C atoms, left it at 28.11 X 10^23?
Answered by
bobpursley
It is not in correct scientific notation, The number is of course, correct.
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