Asked by Andy
What is the [CH3NH3+] of a solution which is 0.1003 M in CH3NH2 and 0.1204 M in CsOH?
CH3NH2(aq) + H2O(l) « CH3NH3+(aq) + OH−(aq)
CH3NH2(aq) + H2O(l) « CH3NH3+(aq) + OH−(aq)
Answers
Answered by
DrBob222
.....CH3NH2 + HOH ==> CH3NH3^+ + OH^-
I...0.1003............0.........0.1204
C.....-x..............x..........x
E...0.1003-x..........x........0.1204+x
Kb = (CH3NH3^+)(OH^-)/[CH3NH3^+]
Look up Kb and plug in the numbers. Solve for x = (CH3NH3^+)
I...0.1003............0.........0.1204
C.....-x..............x..........x
E...0.1003-x..........x........0.1204+x
Kb = (CH3NH3^+)(OH^-)/[CH3NH3^+]
Look up Kb and plug in the numbers. Solve for x = (CH3NH3^+)
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