Asked by Mark
John Davis, a manager of a supermarket, wants to estimate the proportion of customers that will be using food stamps at his store. How large a sample is required to estimate the true proportion to within 3% with 98% confidence?
Answers
Answered by
MathGuru
Formula:
n = [(z-value)(p)(q)]/E^2
z-value = 2.33 for 98% confidence
p = .5 if no value is stated
q = 1 - p
E = Maximum error
With your data:
n = [(2.33)(.5)(.5)]/.03^2
I'll let you take it from here. Round to the next whole number.
n = [(z-value)(p)(q)]/E^2
z-value = 2.33 for 98% confidence
p = .5 if no value is stated
q = 1 - p
E = Maximum error
With your data:
n = [(2.33)(.5)(.5)]/.03^2
I'll let you take it from here. Round to the next whole number.
Answered by
Ashley
647.22
Answered by
Nee
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