Asked by Laura
A moving picture theater usually took in $220 an evening on ticket sales. The manager found out that by reducing the price of tickets by 5 cents, 200 more persons attended, and the box office receipts were $80 more an evening. How many persons attended before the reduction in price?
Answers
Answered by
Steve
If there were normally x tickets sold, the price was 220/x
(220/x-.05)(x+200) = 220+80
x = 400
(220/x-.05)(x+200) = 220+80
x = 400
Answered by
Laura
can you show how the equation is solved?
Answered by
Steve
just like any similar equation...
(220/x-.05)(x+200) = 220+80
(220/x-.05)(x+200) = 300
(220-x/20)(x+200) = 300x
(4400-x)(x+200) = 6000x
-x^2 + 4200x + 880000 = 6000x
x^2 + 1800x - 880000 = 0
(x-400)(x+2200) = 0
(220/x-.05)(x+200) = 220+80
(220/x-.05)(x+200) = 300
(220-x/20)(x+200) = 300x
(4400-x)(x+200) = 6000x
-x^2 + 4200x + 880000 = 6000x
x^2 + 1800x - 880000 = 0
(x-400)(x+2200) = 0
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