Question
2. A point charge of +1.0 µC is moved in the direction of an electric field, and it has a change in electric potential difference energy of 10.0 J. What was the change in electric potential difference? 1 µC = 10-6 C
(Points : 1)
-1.0 × 10^8 V
-1.0 × 10^7 V
+1.0 × 10^7 V
+1.0 × 10^8 V
Question 3.3. A voltmeter reads 200.0 V between parallel plates that are 2.0 cm apart. What is the strength of the electric field between the two plates?
(Points : 1)
1.0 × 10^1 N/C
1.0 × 10^2 N/C
1.0 × 10^3 N/C
1.0 × 10^4 N/C
(Points : 1)
-1.0 × 10^8 V
-1.0 × 10^7 V
+1.0 × 10^7 V
+1.0 × 10^8 V
Question 3.3. A voltmeter reads 200.0 V between parallel plates that are 2.0 cm apart. What is the strength of the electric field between the two plates?
(Points : 1)
1.0 × 10^1 N/C
1.0 × 10^2 N/C
1.0 × 10^3 N/C
1.0 × 10^4 N/C
Answers
Volts + charge = work done
If + charge moves in direction of E field, potential goes down
.02 meters
E = V/d
If + charge moves in direction of E field, potential goes down
.02 meters
E = V/d
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