Asked by Anonymous
A vacuum pump is connected to its electric motor by a belt drive (Fig. 9-40, not to scale). The motor rotates at a rate of 1000 rev/min and the diameter of the motor shaft is 2.9 cm. How large (diameter) should the pulley be if it is designed for a speed of 31 rev/s? (Answer: 1.56cm)
Answer is provided above. Please show all work on how to get the answer as 1.56cm.
Answer is provided above. Please show all work on how to get the answer as 1.56cm.
Answers
Answered by
Anonymous
Diameter = 1000rev/min ÷ 60s * 2π * 2.9cm ÷ (2π * 31rev/s)
Diameter = 1.56cm
Diameter = 1.56cm
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