Asked by Anonymous

Cell Designation : E (measured)
= Sn I Sn^2+ II Cu^2+ I Cu

Temp= 3 Celsius

Temp= 276.15 Kelvin

Delta G= ?????

Show work please!!!!
Answered by Anonymous
I have to use the formula below but I don't know how! :(

Delta G = -nFE
Answered by DrBob222
n = number of electrons transferred. In this case that is 2. Sn ==> Sn^2+ + 2e and Cu^2+ + 2e ==> Cu
F is the Faraday constant of 95,485 coulombs
E is the cell voltage.
T is kelvin temperature. substitute and go. Don't foget the - sign.
Answered by Anonymous
how do i get voltage cell????
Answered by DrBob222
Your post said "E measured" so I assume you have that given to you. If it isn't given, add the oxidation half cell to the reduction half cell to obtain Ecell.
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