Asked by Sha
Balance the redox equation. It occurs in acid solution.
Sn(s) + H+(aq) = Sn2+(aq) + H2(g)
I understand that first the equation needs to be put into halves.
Sn(s) = Sn2+(aq) and H+(aq) = H2(g)
Then,
Sn(s) = Sn2+(aq) + 2e- and ?
From here I am lost. Please help.
Sn(s) + H+(aq) = Sn2+(aq) + H2(g)
I understand that first the equation needs to be put into halves.
Sn(s) = Sn2+(aq) and H+(aq) = H2(g)
Then,
Sn(s) = Sn2+(aq) + 2e- and ?
From here I am lost. Please help.
Answers
Answered by
DrBob222
Sn ==> Sn^2+ + 2e
2H^+ + 2e ==> H2
--------------------add 1 to 2.
Sn + 2H^+ + 2e ==> Sn^2+ + 2e + H2
Then cancel the two e on each side and you're left with the balanced equation.
2H^+ + 2e ==> H2
--------------------add 1 to 2.
Sn + 2H^+ + 2e ==> Sn^2+ + 2e + H2
Then cancel the two e on each side and you're left with the balanced equation.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.