Asked by shoaib
please help me to solve this question
sec^2A+tan^2A=(1-sin^4A)sec^4A
sec^2A+tan^2A=(1-sin^4A)sec^4A
Answers
Answered by
Steve
since sec^2-tan^2=1, you can multiply by that:
(sec^2+tan^2)(sec^2-tan^2)
sec^4-tan^4
but, since tan=sin/cos = sin*sec, that's
sec^4-sin^4*sec^4
(1-sin^4)sec^4
(sec^2+tan^2)(sec^2-tan^2)
sec^4-tan^4
but, since tan=sin/cos = sin*sec, that's
sec^4-sin^4*sec^4
(1-sin^4)sec^4
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