Question
Three green balls and two yellow balls are placed in a hat. Two balls are randomly drawn
without replacement. Let X be the number of green balls drawn.
i)X=1
without replacement. Let X be the number of green balls drawn.
i)X=1
Answers
Reiny
Do you want the probability of drawing 2 green balls?
= (3/5)(2/4) = 3/10
= (3/5)(2/4) = 3/10
SDD
DSFDSA