Asked by Nicole
How many grams of acetic anhydride are needed to react with 3.82g of salicylic acid?
Answers
Answered by
DrBob222
It's one mole to one mol; therefore, how many mols do you have in 3.82 g SA? That's mols SA = 3.82g/molar mass SA.
Then mols AA = mols SA
and g AA = mols AA x molar mass AA
Then mols AA = mols SA
and g AA = mols AA x molar mass AA
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