Question
sweets are shared equally among 20 children at a party. if there were 1 more sweet and 1 more child, each child would get 1 sweet less. how sweets were shared at the party?
thats how the question ends.
thats how the question ends.
Answers
Leo
You might use algebra to solve this. (Hooray! Everyone loves algebra!)
Let's create some variables:
s = number of sweets
n = number of sweets each child gets.
So we have sweets shared equally among 20 children:
s / 20 = n
Also, 1 more sweet and 1 more child means 1 less sweet for each child:
(s + 1) / (20 + 1) = (n - 1)
Does that make sense? If so, can you take it from here?
Let's create some variables:
s = number of sweets
n = number of sweets each child gets.
So we have sweets shared equally among 20 children:
s / 20 = n
Also, 1 more sweet and 1 more child means 1 less sweet for each child:
(s + 1) / (20 + 1) = (n - 1)
Does that make sense? If so, can you take it from here?
Robert
i still have some problems
Leo
Where are you getting stuck exactly? I can't read your mind ya know! ;)