Asked by Anonymous
Dinitrogen tetroxide decomposes to form nitrogen dioxide in a second order reaction:
N2O4(g)-> 2NO2(g)
At 400K, the rate constant for this reaction has been measured to be 2.9x10^8 L/mol*s.suppose 0.222 mol of N2O4(g) is placed in a sealed 41.7L container at 400K and allowed to react. What is the total pressure inside the vessel after 32.9ns has elapsed? (R=0.0821(L*atm)/(K*mol).
N2O4(g)-> 2NO2(g)
At 400K, the rate constant for this reaction has been measured to be 2.9x10^8 L/mol*s.suppose 0.222 mol of N2O4(g) is placed in a sealed 41.7L container at 400K and allowed to react. What is the total pressure inside the vessel after 32.9ns has elapsed? (R=0.0821(L*atm)/(K*mol).
Answers
Answered by
DrBob222
Use the second order rate equation of
(1/A) - (1/Ao) = kt and solve for A at the allotted time. That will give you NO2 also. Convert to mols NO2 and mols N2O4 and use PV = nRT to solve for P. Post your work if you get stuck.
(1/A) - (1/Ao) = kt and solve for A at the allotted time. That will give you NO2 also. Convert to mols NO2 and mols N2O4 and use PV = nRT to solve for P. Post your work if you get stuck.
Answered by
Anonymous
thank you for the walk through.Very helpful.
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