Asked by Lucy
If y^3 = 16x^2
Determine dx/dt
When x= 4 and dy/dt= -1
Determine dx/dt
When x= 4 and dy/dt= -1
Answers
Answered by
Reiny
y^3 = 16x^2
when x = 4
y^3 = 16(256)
y = 16
3y^2 dy/dt = 32x dx/dt
sub in our values
3(256) (-1) = 32(4) dx/dt
dx/dt = -768/128
= -6
when x = 4
y^3 = 16(256)
y = 16
3y^2 dy/dt = 32x dx/dt
sub in our values
3(256) (-1) = 32(4) dx/dt
dx/dt = -768/128
= -6
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