Question

The freezing point of benzene is 5.5°C. What is the freezing point of a solution of 8.50 g of naphthalene (C10H8) in 425 g of benzene (Kf of benzene = 4.90°C/m)?

delta T = K_f m
m = mols/kg solvent.
Change 8.5 g naphthalene to mols and 425 g benzene to kg.
That will get delta T. Then
5.5 - delta T will give the new f.p.
Post your work if you get stuck or if you wish to check your answer.

Answer 1

A 1.60 g sample of napthalene (a non-electrolyte with a formula of C10H8) is dissolved in 20.0 g of benzene (C6H6). The freezing point of benzene is 5.5°C and Kf = 5.12 kg/mol. What is the freezing point of the solution?

Answer 2

What is freezing point depression when 125g of br2 is added to 755g of Benzene? Kf(benzen e = 5.12°C\m.

Answer 3

.553

Answer 4

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