Question

Write the equations below in the form y = mx + c.
State how many solutions each systems of linear equation have.
3x = 6y
2y - 6x + 2 = 0

Answer 1

3x = 6y
looks trivial, just divide by 6

y = (3/6)x + 0
y = (1/2)x + 0

for equations that contain all 3 terms, there is a two-step process

1. move all terms except the y term to the right side of the equal sign
----> 2y = 6x - 2
2. divide each term by the coefficient of the y term,
that is, divide each term by 2
-----> y = 3x - 1
all done!

solving the system:
from the first, after dividing by 3
x = 2y
sub that into the 2nd:
2y - 6(2y) = -2
2y - 12y = -2
-10y = -2

y = 1/5
then x = 2/5