Asked by green
how can i write these equations in standard form with integer coefficients?
so #1 is: y=1/2x-3/5
and also #2: y=-8/3x+4/9
I know the formula is Ax+By=C..
but I just don't get these two..
plz explain & thanks!
so #1 is: y=1/2x-3/5
and also #2: y=-8/3x+4/9
I know the formula is Ax+By=C..
but I just don't get these two..
plz explain & thanks!
Answers
Answered by
Reiny
These require two steps.
1. clear the fractions by multiplying by the LCD
2. rearrange, so the x and y terms are on one side and the constant on the other, leading with a positive coefficient for x
1. multiply by 10
10y = 5x - 6
2. 6 = 5x - 10y or 5x - 10y = 6
Now you try the second in the same way.
1. clear the fractions by multiplying by the LCD
2. rearrange, so the x and y terms are on one side and the constant on the other, leading with a positive coefficient for x
1. multiply by 10
10y = 5x - 6
2. 6 = 5x - 10y or 5x - 10y = 6
Now you try the second in the same way.
Answered by
green
so would number 2 be:
24x+9y=4 OR 4=24x+9y
??
thnx!
24x+9y=4 OR 4=24x+9y
??
thnx!
Answered by
Reiny
Watch your signs
After you multiply by 9 you get
9y = 24x + 4
then 24x - 9y = -4 or -4 = 24x - 9y
the last two equations are the same thing.
(if A=B then B=A)
in the the general form, the x and y terms are "usually" on the left side of the equation, so 24x - 9y = -4 would be preferred.
After you multiply by 9 you get
9y = 24x + 4
then 24x - 9y = -4 or -4 = 24x - 9y
the last two equations are the same thing.
(if A=B then B=A)
in the the general form, the x and y terms are "usually" on the left side of the equation, so 24x - 9y = -4 would be preferred.
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