Asked by thomas
                If the hypotenuse of a right triangle is 10 and one leg is 5 square root 3, then the area of the triangle is 
a. 5
b. 25 square root 3
c. 25
d. 50 square root 3
e. 12.5 square root 3
please answer and explain
            
        a. 5
b. 25 square root 3
c. 25
d. 50 square root 3
e. 12.5 square root 3
please answer and explain
Answers
                    Answered by
            PsyDAG
            
    Use Pythagorean theorem to find other leg.
h^2 + b^2 = Hypotenuse^2
h^2 + (5√3)^2 = 100
Solve for h.
Area = 1/2 hb
Insert values and solve for area.
    
h^2 + b^2 = Hypotenuse^2
h^2 + (5√3)^2 = 100
Solve for h.
Area = 1/2 hb
Insert values and solve for area.
                    Answered by
            thomas
            
    h^2 + 75 = 100
h^2 = 25
h = 5
5 x 5 square root 3 /2
=25 square root 3 /2
= 12.5 square root 3
answer e
right?
    
h^2 = 25
h = 5
5 x 5 square root 3 /2
=25 square root 3 /2
= 12.5 square root 3
answer e
right?
                    Answered by
            PsyDAG
            
    From the way you have your last equation written "square root 3 /2" Looks like √(3/2).
It should be written (25√3)/2. The brackets make the meaning clearer.
The square root sign (√) can be obtained by using "v" and "alt/option" keys simultaneously.
Otherwise, you are right.
    
It should be written (25√3)/2. The brackets make the meaning clearer.
The square root sign (√) can be obtained by using "v" and "alt/option" keys simultaneously.
Otherwise, you are right.
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