Question
the balance equation for the reaction of aqueous sulfuric acid with aqueous ammonia is
2NH3(aq)+ H2SO4(aq) -> (NH4)2SO4(aq)
1. what volume of 0.250M sulfuric acid solution would be needed to react completely with 18.00mL of 0.350M ammonia solution?
2. what mass of ammonium sulfate would be formed by this reaction?
2NH3(aq)+ H2SO4(aq) -> (NH4)2SO4(aq)
1. what volume of 0.250M sulfuric acid solution would be needed to react completely with 18.00mL of 0.350M ammonia solution?
2. what mass of ammonium sulfate would be formed by this reaction?
Answers
1. mols NH3 = M x L = ?
Using the coefficients in the balanced eqauation, convert mols NH3 to mols
H2SO4.
Now M H2SO4 = mols/L, You know mols and M, solve for L and convert to mL if needed.
2.
You have mols NH3. Using the coefficients convert mols NH3 to mols (NH4)2SO4.
Now convert mols to g. g = mols x molar mass
Using the coefficients in the balanced eqauation, convert mols NH3 to mols
H2SO4.
Now M H2SO4 = mols/L, You know mols and M, solve for L and convert to mL if needed.
2.
You have mols NH3. Using the coefficients convert mols NH3 to mols (NH4)2SO4.
Now convert mols to g. g = mols x molar mass
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