Asked by amy
helo sir/madam
can u help me to solve this problem
find the value of x in terms of b of the equation logb 2x-logb(x+2b)=1
can u help me to solve this problem
find the value of x in terms of b of the equation logb 2x-logb(x+2b)=1
Answers
Answered by
Reiny
log<sub>v</sub>[ 2x/(x+2b) [ = 1
2x/(x+2b) = b^1
2x =bx + 2b^2
2x - bx = 2b^2
x(2 - b) = 2b^2
x = 2b^2/(2 - b)
2x/(x+2b) = b^1
2x =bx + 2b^2
2x - bx = 2b^2
x(2 - b) = 2b^2
x = 2b^2/(2 - b)
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